Optimal. Leaf size=297 \[ \frac{2 \left (-6 a^2 B+21 a A b+25 b^2 B\right ) \sin (c+d x) \sqrt{a+b \cos (c+d x)}}{105 b d}-\frac{2 \left (a^2-b^2\right ) \left (-6 a^2 B+21 a A b+25 b^2 B\right ) \sqrt{\frac{a+b \cos (c+d x)}{a+b}} F\left (\frac{1}{2} (c+d x)|\frac{2 b}{a+b}\right )}{105 b^2 d \sqrt{a+b \cos (c+d x)}}+\frac{2 \left (21 a^2 A b-6 a^3 B+82 a b^2 B+63 A b^3\right ) \sqrt{a+b \cos (c+d x)} E\left (\frac{1}{2} (c+d x)|\frac{2 b}{a+b}\right )}{105 b^2 d \sqrt{\frac{a+b \cos (c+d x)}{a+b}}}+\frac{2 (7 A b-2 a B) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{35 b d}+\frac{2 B \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 b d} \]
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Rubi [A] time = 0.527524, antiderivative size = 297, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 8, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.258, Rules used = {2968, 3023, 2753, 2752, 2663, 2661, 2655, 2653} \[ \frac{2 \left (-6 a^2 B+21 a A b+25 b^2 B\right ) \sin (c+d x) \sqrt{a+b \cos (c+d x)}}{105 b d}-\frac{2 \left (a^2-b^2\right ) \left (-6 a^2 B+21 a A b+25 b^2 B\right ) \sqrt{\frac{a+b \cos (c+d x)}{a+b}} F\left (\frac{1}{2} (c+d x)|\frac{2 b}{a+b}\right )}{105 b^2 d \sqrt{a+b \cos (c+d x)}}+\frac{2 \left (21 a^2 A b-6 a^3 B+82 a b^2 B+63 A b^3\right ) \sqrt{a+b \cos (c+d x)} E\left (\frac{1}{2} (c+d x)|\frac{2 b}{a+b}\right )}{105 b^2 d \sqrt{\frac{a+b \cos (c+d x)}{a+b}}}+\frac{2 (7 A b-2 a B) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{35 b d}+\frac{2 B \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{7 b d} \]
Antiderivative was successfully verified.
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Rule 2968
Rule 3023
Rule 2753
Rule 2752
Rule 2663
Rule 2661
Rule 2655
Rule 2653
Rubi steps
\begin{align*} \int \cos (c+d x) (a+b \cos (c+d x))^{3/2} (A+B \cos (c+d x)) \, dx &=\int (a+b \cos (c+d x))^{3/2} \left (A \cos (c+d x)+B \cos ^2(c+d x)\right ) \, dx\\ &=\frac{2 B (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{7 b d}+\frac{2 \int (a+b \cos (c+d x))^{3/2} \left (\frac{5 b B}{2}+\frac{1}{2} (7 A b-2 a B) \cos (c+d x)\right ) \, dx}{7 b}\\ &=\frac{2 (7 A b-2 a B) (a+b \cos (c+d x))^{3/2} \sin (c+d x)}{35 b d}+\frac{2 B (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{7 b d}+\frac{4 \int \sqrt{a+b \cos (c+d x)} \left (\frac{1}{4} b (21 A b+19 a B)+\frac{1}{4} \left (21 a A b-6 a^2 B+25 b^2 B\right ) \cos (c+d x)\right ) \, dx}{35 b}\\ &=\frac{2 \left (21 a A b-6 a^2 B+25 b^2 B\right ) \sqrt{a+b \cos (c+d x)} \sin (c+d x)}{105 b d}+\frac{2 (7 A b-2 a B) (a+b \cos (c+d x))^{3/2} \sin (c+d x)}{35 b d}+\frac{2 B (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{7 b d}+\frac{8 \int \frac{\frac{1}{8} b \left (84 a A b+51 a^2 B+25 b^2 B\right )+\frac{1}{8} \left (21 a^2 A b+63 A b^3-6 a^3 B+82 a b^2 B\right ) \cos (c+d x)}{\sqrt{a+b \cos (c+d x)}} \, dx}{105 b}\\ &=\frac{2 \left (21 a A b-6 a^2 B+25 b^2 B\right ) \sqrt{a+b \cos (c+d x)} \sin (c+d x)}{105 b d}+\frac{2 (7 A b-2 a B) (a+b \cos (c+d x))^{3/2} \sin (c+d x)}{35 b d}+\frac{2 B (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{7 b d}-\frac{\left (\left (a^2-b^2\right ) \left (21 a A b-6 a^2 B+25 b^2 B\right )\right ) \int \frac{1}{\sqrt{a+b \cos (c+d x)}} \, dx}{105 b^2}+\frac{\left (21 a^2 A b+63 A b^3-6 a^3 B+82 a b^2 B\right ) \int \sqrt{a+b \cos (c+d x)} \, dx}{105 b^2}\\ &=\frac{2 \left (21 a A b-6 a^2 B+25 b^2 B\right ) \sqrt{a+b \cos (c+d x)} \sin (c+d x)}{105 b d}+\frac{2 (7 A b-2 a B) (a+b \cos (c+d x))^{3/2} \sin (c+d x)}{35 b d}+\frac{2 B (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{7 b d}+\frac{\left (\left (21 a^2 A b+63 A b^3-6 a^3 B+82 a b^2 B\right ) \sqrt{a+b \cos (c+d x)}\right ) \int \sqrt{\frac{a}{a+b}+\frac{b \cos (c+d x)}{a+b}} \, dx}{105 b^2 \sqrt{\frac{a+b \cos (c+d x)}{a+b}}}-\frac{\left (\left (a^2-b^2\right ) \left (21 a A b-6 a^2 B+25 b^2 B\right ) \sqrt{\frac{a+b \cos (c+d x)}{a+b}}\right ) \int \frac{1}{\sqrt{\frac{a}{a+b}+\frac{b \cos (c+d x)}{a+b}}} \, dx}{105 b^2 \sqrt{a+b \cos (c+d x)}}\\ &=\frac{2 \left (21 a^2 A b+63 A b^3-6 a^3 B+82 a b^2 B\right ) \sqrt{a+b \cos (c+d x)} E\left (\frac{1}{2} (c+d x)|\frac{2 b}{a+b}\right )}{105 b^2 d \sqrt{\frac{a+b \cos (c+d x)}{a+b}}}-\frac{2 \left (a^2-b^2\right ) \left (21 a A b-6 a^2 B+25 b^2 B\right ) \sqrt{\frac{a+b \cos (c+d x)}{a+b}} F\left (\frac{1}{2} (c+d x)|\frac{2 b}{a+b}\right )}{105 b^2 d \sqrt{a+b \cos (c+d x)}}+\frac{2 \left (21 a A b-6 a^2 B+25 b^2 B\right ) \sqrt{a+b \cos (c+d x)} \sin (c+d x)}{105 b d}+\frac{2 (7 A b-2 a B) (a+b \cos (c+d x))^{3/2} \sin (c+d x)}{35 b d}+\frac{2 B (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{7 b d}\\ \end{align*}
Mathematica [A] time = 1.00906, size = 233, normalized size = 0.78 \[ \frac{b (a+b \cos (c+d x)) \left (\left (12 a^2 B+168 a A b+115 b^2 B\right ) \sin (c+d x)+3 b (2 (8 a B+7 A b) \sin (2 (c+d x))+5 b B \sin (3 (c+d x)))\right )+4 \sqrt{\frac{a+b \cos (c+d x)}{a+b}} \left (b^2 \left (51 a^2 B+84 a A b+25 b^2 B\right ) F\left (\frac{1}{2} (c+d x)|\frac{2 b}{a+b}\right )+\left (21 a^2 A b-6 a^3 B+82 a b^2 B+63 A b^3\right ) \left ((a+b) E\left (\frac{1}{2} (c+d x)|\frac{2 b}{a+b}\right )-a F\left (\frac{1}{2} (c+d x)|\frac{2 b}{a+b}\right )\right )\right )}{210 b^2 d \sqrt{a+b \cos (c+d x)}} \]
Antiderivative was successfully verified.
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Maple [B] time = 4.073, size = 1305, normalized size = 4.4 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (B \cos \left (d x + c\right ) + A\right )}{\left (b \cos \left (d x + c\right ) + a\right )}^{\frac{3}{2}} \cos \left (d x + c\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (B b \cos \left (d x + c\right )^{3} + A a \cos \left (d x + c\right ) +{\left (B a + A b\right )} \cos \left (d x + c\right )^{2}\right )} \sqrt{b \cos \left (d x + c\right ) + a}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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